${x^4}$ ${-5x+6}$
${-x^2+2}$
$-x^2$
$-2$
${x^4}$ ${- 2x^2}$
($-$)
($+$)
$2x^2 - 5x+6 $
${2x^2}$ ${-4}$
($-$)
($+$)
$-5x +10$
Therefore:$x^4 – 5x + 6$ = $(2 – x^2)(-x^2-2) + (-5x+10) $
${x^4}$ ${-5x+6}$
($+$)
${2x^2}$ ${-4}$
($+$)