$x^3 – 3x^2 + 5x – 3$
$x^2 – 2$
$x$
$- 3$
${ x^3}$    ${-2x} $
($-$)
    ($+$)
$-$
$3x^2+7x-3$
$-$
${3x^2}$      ${+6}$
($+$)
   ($-$)
$7x-9$


Therefore: $x^3 – 3x^2 + 5x – 3$ = $(x^2 – 2)(x-3) + (7x-9)$